A piece of copper of mass 20g at a temperature of 110°C was dropped into a mixture of ice and water at 0°C. If the final steady temperature of the mixture is 0°C . Calculate the amount of ice that melted [Specific heat capacity of copper = 0.4 Jg(^{-1})K(^{-1}), specific latent heat of fusion of ice = 330Jg(^{-1})]
-
A.
0.37g -
B.
0.60g -
C.
2.40g -
D.
2.70g
Correct Answer: Option D
Explanation
Mice = (frac{MC}{theta})
= (frac{20 times 0.4 times 110}{330}
Heat lost by copper = Heat gained by ice
m(_{copper}) c (theta) = m(_{ice}) L
20 x 0.4 x (110 – 0) = m(_{ice}) x 330
m(_{ice}) = (frac{20 times 0.4 times 110}{330})
= (frac{8}{3})
= 2.67 g
= 2.70g (to 1 d.p)