A particle is projected horizontally at 15ms(^{-1}) from a height of 20m.
Calculate the horizontal distance covered by the particle just before hitting the ground.
Explanation
The expected answer is:
Let R represent the horizontal distance covered at time, t.
h = ½ gt(^2)
20 = ½ x 10 x t(^2)
t = 2 s
R = ut
= 15 x 2
= 30m