A man walks 1km due east and then 1km due north. His displacement is
-
A.
1 km N15oE -
B.
1 km N30oE -
C.
(sqrt 2)km N 45oE -
D.
(sqrt 2)km N 60oE -
E.
2km N 75oE
Correct Answer: Option C
Explanation
R = (sqrt{1^2 + 1^2}) = (sqrt{2km})
(theta) = tan-1 (frac{(1)}{1}) = 45oC
= (sqrt 2)km N 45oE