A football is kicked at an angle of 45° to the horizontal over a defense line up with a velocity of 15(ms^{-1}). Calculate the magnitudeof horizontal velocity of the ball at its highest point [Neglect friction, g = 10(ms^{-2})].
-
A.
0.0(ms^{-1}) -
B.
5.6(ms^{-1}) -
C.
10.6(ms^{-1}) -
D.
15.0(ms^{-1})
Correct Answer: Option C
Explanation
The horizontal component of velocity, (V_{x}), is unaffected by the acceleration of free fall and remains constant.
(V_{x} = U_{x} = Ucostheta)
= (15 times cos45 = 15times 0.7071)
(approxeq 10.6ms^{-1})