A feasible cell was constructed by joining the two half cells below. Cu2+ (aq) +…

A feasible cell was constructed by joining the two half cells below. Cu2+(aq) + 2e- → Cu(s) Eo = – 0.76 V. What is the standard e.m.f. of the cell?
  • A.
    – 1.1V
  • B.
    – 0.42V
  • C.
    +0.42V
  • D.
    +1.1V
Correct Answer: Option D
Explanation

e.m.f. = + 0.34 -(-0.76) = 0.34 + 0.76 = +1.1V

You May Also Like