200cm(^3) of 0.50mol/dm(^3) solution of calcium hydrogen trioxocarbonate (IV) is heated. The maximum weight of solid precipitated is
-
A.
10g -
B.
25g -
C.
20g -
D.
15g
Correct Answer: Option A
Explanation
Equation: Ca(HCO(_3))(_2) (to) CaCO(_3) (precipitate) + H(_2)O + CO(_2) (in the presence of heat)
V = 200 cm(^3) = 0.2 dm(^3)
C = 0.5 mol/dm(^3) = 0.5M
N = CV (implies) N = 0.5 (times) 0.2
= 0.1 mole
From the equation 1 mole of Ca(HCO(_3))(_2) gives 100g of CaCO(_3)
(1 mole CaCO(_3) = 40 + 12 + (3 x 16) = 100g)
0.1 mole of Ca(HCO(_3))(_2) gives x g of CaCO(_3).
(frac{1}{0.10} = frac{100}{x})
(x = 100 times 0.10 = 10 g)
There is an explanation video available below.