1.00g of mixture of calcium carbonate and calcium oxide liberated 0.33g of carbon dioxide on strong heating. The percentage of calcium oxide in the mixture is? (Ca = 40, C = 12, O = 16)
-
A.
5 -
B.
15 -
C.
25 -
D.
35 -
E.
50
Correct Answer: Option C
Explanation
CaCO3 + CaO (to) 2CaO + 2CO2
44gm of CO3 is liberated by 100gm of CaCO3
0.33gm of CO2 will be liberated by (frac{100}{44}) x 0.33
= 0.75 of CaCO3
Amount of CaO = 1 – 0.75
= 0.25
% of CaO = (frac{0.25}{1} times frac{100}{1})
= 25%